For working professionals
For fresh graduates
More
6. JDK in Java
7. C++ Vs Java
16. Java If-else
18. Loops in Java
20. For Loop in Java
46. Packages in Java
53. Java Collection
56. Generics In Java
57. Java Interfaces
60. Streams in Java
63. Thread in Java
67. Deadlock in Java
74. Applet in Java
75. Java Swing
76. Java Frameworks
78. JUnit Testing
81. Jar file in Java
82. Java Clean Code
86. Java 8 features
87. String in Java
93. HashMap in Java
98. Enum in Java
101. Hashcode in Java
105. Linked List in Java
109. Array Length in Java
111. Split in java
112. Map In Java
115. HashSet in Java
118. DateFormat in Java
121. Java List Size
122. Java APIs
128. Identifiers in Java
130. Set in Java
132. Try Catch in Java
133. Bubble Sort in Java
135. Queue in Java
142. Jagged Array in Java
144. Java String Format
145. Replace in Java
146. charAt() in Java
147. CompareTo in Java
151. parseInt in Java
153. Abstraction in Java
154. String Input in Java
156. instanceof in Java
157. Math Floor in Java
158. Selection Sort Java
159. int to char in Java
164. Deque in Java
172. Trim in Java
173. RxJava
174. Recursion in Java
175. HashSet Java
177. Square Root in Java
190. Javafx
A string is simply a sequence of characters (like words or sentences). Both Java and C++ let you work with text, but they handle strings in different ways. In Java, strings are objects of the java.lang.String class with many built-in methods.
In C++, you have two main choices: traditional C-style character arrays or the modern std::string class from the standard library. This guide explains these differences with clear examples and practical tips.
You can also explore our in-depth Software engineering courses.
In Java, a string literal (text in quotes) automatically creates a String object. For example:
String greeting = "Hello";
System.out.println(greeting);
Output:
Hello
Here, greeting refers to a String object holding "Hello". Java String objects are immutable – their contents cannot be changed once created. If you try to modify a string, Java actually makes a new object. For example:
String s = "abc";
s = s.toUpperCase(); // returns "ABC"
After this, s refers to a new string "ABC", and the original "abc" remains unchanged. Java also uses a string pool in memory to save space. Identical string literals share the same object. For instance:
String a = "cat";
String b = "cat";
Here both a and b point to the same string object in the pool.
Java provides many useful methods of Strings (length(), substring(), equals(), etc.) and supports the + operator for concatenation. Under the hood, + uses a StringBuilder for efficiency. For example:
String name = "Anika";
String message = "Hello, " + name + "!";
System.out.println(message);
Output:
Hello, Anika!
Stay ahead with these handpicked, high-impact courses.
C++ offers two main approaches:
This is the classic C approach. A string is a char array ending with a null character '\0'. For example:
char greeting[] = "Hello";
std::cout << greeting << std::endl;
Output:
Hello
Under the hood, greeting is a 6-element array: {'H','e','l','l','o','\0'}. The '\0' marks the end of the string. You must ensure the array is large enough for all characters plus the null terminator. C-style strings are mutable (you can change individual characters) but their size is fixed at compile time.
Also read: Substrings in C++: Complete Guide & Examples
This is a C++ class for dynamic strings. It automatically manages memory and can grow or shrink. For example:
#include <iostream>
#include <string>
int main() {
std::string greeting = "Hello";
std::string name = "Bunny";
std::string message = greeting + ", " + name + "!";
std::cout << message << std::endl;
return 0;
}
Output:
Hello, Bunny!
std::string objects are mutable (you can modify them). They offer many methods like length(), substr(), append(), etc. A std::string handles its own memory internally, so you don’t have to allocate a buffer yourself.
In Java, string literals (e.g. "hello") are stored in a special constant pool in the heap. For example,
String a = "hello";
String b = "hello";
makes both a and b refer to the same object in the pool. Using new String("hello") still uses the pool for characters but creates a separate object on the heap. Java’s garbage collector automatically frees String objects that are no longer used.
In C++, memory use depends on the type. A char[] is allocated with a fixed size (often on the stack). Exceeding that size causes errors. In contrast, std::string allocates on the heap and grows as needed. When a std::string grows beyond its capacity, it allocates a new, larger block of memory and copies the contents. The old block is then freed. This means you don’t need to manage memory yourself when using std::string.
Java example:String user = "Anika";
System.out.println("Hello, " + user + "!");
Output:
Hello, Anika!
C++ example:std::string user = "Bunny";
std::cout << "Hello, " << user << "!" << std::endl;
Output:
Hello, Bunny!
Understanding these differences helps you write clearer, more efficient code when working with text in either language.
Java Strings are immutable for security, thread safety, and memory efficiency. Once created, they can't change. In contrast, C++ std::string is mutable to give more control over memory and performance, letting developers modify string content directly without creating new objects each time.
C++ std::string is generally more memory-efficient because it avoids the overhead of Java’s object model and garbage collector. However, Java’s string pool reuses literals to save memory. The efficiency depends on how strings are used and managed in each language.
In Java, you can't resize a String since it’s immutable. You’d need to use StringBuilder for that. In C++, std::string supports dynamic resizing with methods like .resize() or .append(), making it flexible for modifying or extending content on the fly.
Java uses the + operator for String concatenation, which internally uses StringBuilder. C++ allows + with std::string, which performs direct memory appends. However, for efficiency in loops, Java prefers StringBuilder, while C++ can use .append() or ostringstream.
No. In Java, use .equals() to compare string content and == for reference comparison. In C++, use == with std::string, but for C-style char[], use strcmp() as == compares memory addresses, not the actual character data.
It’s not recommended unless required for backward compatibility with legacy C code. C-style strings are prone to buffer overflows and require manual memory management. Prefer std::string in modern C++ for safety, easier syntax, and automatic memory handling.
Java String uses UTF-16 encoding by default. C++ std::string is encoding-agnostic and typically holds ASCII or UTF-8 data. For proper Unicode support in C++, developers often use libraries like ICU or switch to std::wstring or std::u16string.
C++ offers more control over memory and may perform better in raw speed with large strings, especially using std::string::reserve(). However, Java provides built-in memory management and tools like StringBuilder, which make large operations easier to implement and safer.
Yes, but with differences. In Java, a String can be null, causing a NullPointerException if accessed. In C++, a std::string object is never null once initialized, but pointers to strings (char*) can be null and must be checked carefully.
Java uses automatic garbage collection to clean up unused String objects. In C++, memory for std::string is released automatically when the object goes out of scope. For char* or manually allocated memory, you must use delete or free explicitly.
No. Java String is immutable, so you can’t modify it using indexing. You can read characters using charAt(), but for modifications, you must use StringBuilder. In C++, std::string allows direct character modification using indexing, like s[0] = 'A';.
Take the Free Quiz on Java
Answer quick questions and assess your Java knowledge
Author|900 articles published
Previous
Next
Talk to our experts. We are available 7 days a week, 9 AM to 12 AM (midnight)
Indian Nationals
1800 210 2020
Foreign Nationals
+918068792934
1.The above statistics depend on various factors and individual results may vary. Past performance is no guarantee of future results.
2.The student assumes full responsibility for all expenses associated with visas, travel, & related costs. upGrad does not provide any a.